[cs13001] L19 Question

[Mikhail Nesterenko]

  > 
1 >     int *ip1, *ip2, one = 1, two = 2;
2 > 
3 >     ip1 = &one;
4 >     ip2 = ip1;
5 >     *ip1 = *ip1 + 1;
6 >     ip1 = &two;
7 >     *ip1 -= 1;
8 >     cout << *ip2 << ' ' << *ip1 << endl;
  > 
  > how exactly is the output of *ip2 equal to 2 ?  I don't get it,
  > shouldn't be equal to 1 like *ip1 ?

In line 5, both ip1 and ip2 point to variable "one", whose value by then
is 2

In line 6, ip1 starts pointing to variable "two". On line 7, the value
of this variable is decreased from 2 to 1.

Thanks,
-- 
Mikhail